What is the energy difference between the two quantum states involved in the transition of red light with wavelength 705 nm being absorbed by an atomic gas?

1 Answer
Gió
Jun 22, 2015

I found:
E=h*nu=2.82xx10^-19J=1.76eV

Explanation:

A wavelength of 705 nm corresponds to a frequency:
nu=c/lambda=(3xx10^8)/(7.05xx10^-7)=4.25xx10^14Hz

From Einstein's Relatonship you have that the photon energy will be:

color(red)(E=h*nu)=6.63xx10^-34*4.25xx10^14=2.82xx10^-19J=1.76eV

This is exactly the energy gap (or difference) between the two quantum states involved in the absorption of your photon of red light.

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