What is the empirical formula of a compound if it has 80g Ca and 70g Cl?

1 Answer
anor277
Aug 12, 2017

CaCl....

Explanation:

We determine the number of moles of calcium and chlorine respectively....

"Moles of calcium"=(80*g)/(40.1*g*mol^-1)=2.0*mol

"Moles of chlorine"=(70*g)/(35.45*g*mol^-1)=2.0*mol

We divide thru by the smallest molar quantity to get CaCl; a Ca(+I) salt that I don't think is known.

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