What is the empirical formula for the compound which is comprised of 2.677 g Ba and 3.115 g Br?

1 Answer
Jarni Renz
Feb 27, 2016

#BaBr_2#

Explanation:

Masses:
#Ba=2.677g#
#Br=3.115g#

Atomic Masses:

#Ba=137.327g/(mol)#
#Br=79.904g/(mol)#

Looking for the values in mol:
#Ba=2.677cancel(gBa)# #xx# #(1molBa)/(137.327cancel(gBa)# = #0.01949molBa#
#Br=3.115cancel(gBr)# #xx# #(1molBr)/(79.904cancel(gBr)#=#0.038983molBr#

Therefore:
#Ba# = #(0.01949mol)/(0.01949mol)#=1
#Br#=#(0.03898mol)/(0.01949mol)#=2

Empirical Formula#=BaBr_2#

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