What is the electron configuration of an element with atomic number 110?

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Answer 1 · 2017-05-29T13:43:16

Element 110 is thought to have the electron configuration $[R n] 5 f^{14} 6 d^{8} 7 s^{2}$ $[Rn] 5f^(14)6d^8 7s^2$

Element 110 is Darmstadtium (Ds) named after a town in Germany. Much about it is unknown. It is thought to have the electron configuration:

$D s = [R n] 5 f^{14} 6 d^{8} 7 s^{2}$ $Ds=[Rn] 5f^(14)6d^8 7s^2$

This is using the notation based on increments from the nearest noble gas in this case Radon.

To complete the picture Radon's electron configuration is based on increments from Xenon:

$R n = [X e] 4 f^{14} 5 d^{10} 6 s^{2} 6 p^{6}$ $Rn=[Xe] 4f^(14)5d^(10) 6s^2 6p^6$

Likewise:

$X e = [K r] 4 d^{10} 5 s^{2} 5 p^{6}$ $Xe=[Kr] 4d^(10)5s^2 5p^6$

$K r = [A r] 3 d^{10} 4 s^{2} 4 p^{6}$ $Kr=[Ar] 3d^(10)4s^2 4p^6$

$A r = [N e] 3 s^{2} 3 p^{6}$ $Ar=[Ne] 3s^2 3p^6$

$N e = [H e] 2 s^{2} 2 p^{6}$ $Ne=[He] 2s^2 2p^6$

$H e = 1 s^{2}$ $He=1s^2$