What is the electron configuration for nickel, whose atomic number is 28?

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What is the electron configuration for nickel, whose atomic number is 28?

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Answer 1 · 2016-07-02T15:23:06

$N i = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{8}$ $Ni = 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^8$

$N i = [A r] 4 s^{2} 3 d^{8}$ $Ni = [Ar] 4s^2 3d^8$

Explanation:

Nickel is in the $4 t h$ $4th$ energy level, $d$ $d$ block, $7 t h$ $7th$ column, this means that the electron configuration will end $3 d^{8}$ $3d^8$ with the $d$ $d$ orbital being one level lower than the energy level it is on.

$N i = 1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{8}$ $Ni = 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^8$

$N i = [A r] 4 s^{2} 3 d^{8}$ $Ni = [Ar] 4s^2 3d^8$

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What is the electron configuration for nickel, whose atomic number is 28?

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