What is the domain of the function: $x \sqrt{9 - x^{2}}$ $x sqrt(9-x^2)$ ?

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Answer 1 · 2016-01-10T20:23:41

The argument of the square root function must be $\geq 0$ $>=0$

$9 - x^{2} \geq 0$ $9-x^2>=0$

$- x^{2} \geq - 9$ $-x^2>=-9$

$x^{2} \leq 9$ $x^2<=9$

Domain : $- 3 \leq x \leq 3$ $-3<=x<=3$

hope that helped

What is the domain of the function: x√9−x2x sqrt(9-x^2)?