What is the domain of the function p(w)=2/(3w^9)p(w)=23w9?

1 Answer
KillerBunny · mason m
Jan 23, 2015

You have a fractions, so the only thing you must be sure of is that the denominator is not zero.

In your case, the denominator is given by the function f(w)=3w^9f(w)=3w9. You need to find out the values of ww for which f(w)=0f(w)=0. You have
f(w)=0 \iff 3w^9=0 \iff w^9=0 \iff w=^9\sqrt0=0f(w)=0⇔3w9=0⇔w9=0⇔w=9√0=0

So, your only problem is w=0w=0, and all other numbers are fine.

Your domain is thus given by the set {x \in \mathbb{R} | x \ne 0}

The domain can also be written as (-oo,0)uu(0,+oo).

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