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What is the domain of the function: #f(x) =sqrt(x^2 - 2x + 5)#?

1 Answer

Sep 17, 2015

#D_f=R#

Explanation:

#x^2-2x+5>=0#

#D=b^2-4ac=(-2)^2-4*1*5=4-20=-16#

Because #D<0# and #a=1>0#, expression #x^2-2x+5>0# for #AAx in R# and square root can be calculated. Hence,

#D_f=R#

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