What is the domain of h(x)=sqrt(x-2)?

1 Answer
NJ
Jun 17, 2018

x in [2, infty)

Explanation:

For radical functions, we cannot have a quantity less than 0 inside the square root.

In this case, we know that h(2) = 0, but if x is decreased any more than this, the radical will be undefined.

So we know that x = 2 is the minimum value of the domain. As we increase x, we have no issues as the radical always contains a positive number. So x -> infty.

So the domain would be all values of x >= 2, or

x in [2, infty)

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