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What is the domain of #f(x) = sqrt(x^2-144)#?

1 Answer

May 18, 2018

#x >= 12 and x <= -12#

Explanation:

#x^2 - 144 >=0# or the value under the radical in imaginary:

#x^2 >=144#

#x >= +-sqrt144#

#x >= +-12#

#x >= 12 and x <= -12#

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