What is the domain of $f (x) = \sqrt{x^{2} - 144}$ $f(x) = sqrt(x^2-144)$ ?

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Answer 1 · 2018-05-18T22:30:34

$x \geq 12 and x \leq - 12$ $x >= 12 and x <= -12$

$x^{2} - 144 \geq 0$ $x^2 - 144 >=0$ or the value under the radical in imaginary:

$x^{2} \geq 144$ $x^2 >=144$

$x \geq \pm \sqrt{144}$ $x >= +-sqrt144$

$x \geq \pm 12$ $x >= +-12$

$x \geq 12 and x \leq - 12$ $x >= 12 and x <= -12$

What is the domain of f(x)=√x2−144f(x) = sqrt(x^2-144)?