What is the domain and range of y(x)=ln(x+2)?

1 Answer
May 21, 2018

The domain is x in (-2, +oo).
The range is y in RR

Explanation:

What's in the log function is >0

Therefore,

x+2 >0

x > -2

The domain is x in (-2, +oo)

Let y=ln(x+2)

x+2=e^y

x=e^y-2

AA y in RR, e^y>0

The range is y in RR

graph{ln(x+2) [-8.54, 23.5, -9.32, 6.7]}