What is the domain and range of $y=x^2 - 4x + 1$ ?

Question

8453 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-23T20:44:29

Range: $y>=-3$
Domain: $x in RR$

Complete the square (putting the function in vertex form)

$y=(x-2)^2-4+1$
$y=(x-2)^2-3$

Hence the minimum of the function is $y=-3$ , so we can say that the range is

$y>=-3$

As for the domain, any value of $x$ can be passed to the function so we say that the domain is

$x in RR$

What is the domain and range of y=x^2 - 4x + 1y=x^2 - 4x + 1?