What is the domain and range of $y=sqrt((x² - 8) )$ ?

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Answer 1 · 2016-06-03T13:09:51

Domain: $(-oo, -sqrt8] uu [sqrt8, +oo)$
Range: $y>=0$

For the domain of $y=sqrt(x^2-8)$
$x$ can not be in between $-sqrt8$ and $sqrt8$

Domain: $(-oo, -sqrt8] uu [sqrt8, +oo)$

Range: $y>=0$

kindly see the graph
graph{(y-sqrt(x^2-8))=0[-20,20,-10,10]}

God bless....I hope the explanation is useful

What is the domain and range of y=sqrt((x² - 8) )y=sqrt((x² - 8) )?