What is the domain and range of y =sqrt(x-3) - sqrt(x+3)?

3 Answers
Jul 2, 2018

Domain: [3, oo) " or " x >= 3

Range: [-sqrt(6), 0) " or " -sqrt(6) <= y < 0

Explanation:

Given: y = sqrt(x-3) - sqrt(x + 3)

Both the domain is the valid inputs x. The range is the valid outputs y.

Since we have two square roots, the domain and the range will be limited.

color(blue)"Find the Domain:"

The terms under each radical must be >= 0:

x - 3 >= 0; " " x + 3 >= 0

x >= 3; " "x >= -3

Since the first expression must be >=3, this is what limits the domain.

Domain: [3, oo) " or " x >= 3

color(red)"Find the Range:"

The range is based on the limited domain.

Let x = 3 => y = sqrt(3-3) - sqrt(3+3) = -sqrt(6)

Let x = 100 => y = sqrt(97) - sqrt(103) ~~-.3

Let x = 1000 => y = sqrt(997) - sqrt(1003) ~~-.09

x -> oo, y -> 0

Range: [-sqrt(6), 0) " or " -sqrt(6) <= y < 0

Jul 2, 2018

The domain is x in [3,+oo). The range is y in [-sqrt(6),0^-)

Explanation:

What's under the sqrt sign must be >=0

=>, x-3>=0 and x+3>=0

=>, {(x>=3),(x>=-3):}

Therefore,

The domain is (x>=3)nn(x>=-3)

That is, x in [3,+oo)

When x=3, =>, y=0-sqrt6

And when x->+oo

lim_(x->+oo)y=0^-

Therefore,

The range is y in [-sqrt(6),0^-)

graph{sqrt(x-3)-sqrt(x+3) [-1.42, 18.58, -6.36, 3.64]}

Jul 2, 2018

Domain: [3, oo)

Range: [-sqrt(6), 0)

Explanation:

Given:

y = sqrt(x-3)-sqrt(x+3)

First note that the square roots are well defined and real if and only if x-3 >= 0 and x+3 >= 0. Hence it is necessary and sufficient that x >= 3.

So the domain of the function is [3, oo)

To find the range, note that when x = 3 then:

y = sqrt((color(blue)(3))-3)-sqrt((color(blue)(3))+3) = sqrt(0)-sqrt(6) = -sqrt(6)

We find:

lim_(x->oo) (sqrt(x-3)-sqrt(x+3)) = lim_(x->oo) ((sqrt(x-3)-sqrt(x+3))(sqrt(x-3)+sqrt(x+3)))/(sqrt(x-3)+sqrt(x+3))

color(white)(lim_(x->oo) (sqrt(x-3)-sqrt(x+3))) = lim_(x->oo) ((x-3)-(x+3))/(sqrt(x-3)+sqrt(x+3))

color(white)(lim_(x->oo) (sqrt(x-3)-sqrt(x+3))) = lim_(x->oo) (-6)/(sqrt(x-3)+sqrt(x+3))

color(white)(lim_(x->oo) (sqrt(x-3)-sqrt(x+3))) = 0

Note that -6/(sqrt(x-3)+sqrt(x+3)) is continuous and monotonically increasing.

Hence the range of the given function runs from the minimum value -sqrt(6) up to but not including the limit 0.

That is, the range is [-sqrt(6), 0)

graph{y = sqrt(x-3)-sqrt(x+3) [-10, 10, -5, 5]}