What is the domain and range of y =sqrt (x^2 - 9)?

1 Answer
Jim G.
Mar 18, 2018

x<=-3" or "x>=3
y inRR,y>=0

Explanation:

"for the domain we require"

x^2-9>=0

rArrx^2>=9

rArrx<=-3" or "x>=3

"domain is "(-oo,-3]uu[3,+oo)

"range is "y inRR,y>=0
graph{sqrt(x^2-9) [-10, 10, -5, 5]}

Related questions
See all questions in Domain and Range of a Function
Impact of this question
49884 views around the world
You can reuse this answer
Creative Commons License