What is the domain and range of y =sqrt(17x+8)?

1 Answer
Leland Adriano Alejandro
Feb 28, 2016

Domain: x>=-8/17 or Domain:[-8/17, +oo)
Range:y>=0 or Range:[0, +oo)

Explanation:

The square root of a negative number is an imaginary number.
The square root of zero is zero. The radicand is zero at x=-8/17.
Any value greater than -8/17 will result to a positive radicand.
Therefore, Domain: x>=-8/17

Range: is 0 to +infinity

God bless...I hope the explanation is useful..

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