What is the domain and range of $y=ln(x-3)+1$ ?

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Answer 1 · 2016-02-14T03:39:40

The domain is $x>3$ .

The range is any real number.

Because $ln(x)$ only takes input for $x>0$ , $ln(x-3)$ only takes input for $x>3$ .

The following is a graph of $y=ln(x-3)+1$

graph{ln(x-3)+1 [-10, 10, -5, 5]}

It ranges from $-oo$ to $oo$ .

What is the domain and range of y=ln(x-3)+1y=ln(x-3)+1?