What is the domain and range of y=-3(x-10)^2+5?

1 Answer
Nov 10, 2017

Domain: x in RR or (-oo,oo)
Range: y<=5 or [-oo,5]

Explanation:

y= -3(x-10)^2+5 . This is vertex form of equation of parabola

having vertex at (10,5) [ Comparing with vertex form of

equation f(x) = a(x-h)^2+k ; (h,k) being vertex we find

here h=10 , k=5 , a=-3 ] . Since a is negative the parabola

opens downward , vertex is the maximum point of y.

Domain: Any real number of x is possible as input.

So Domain: x in RR or (-oo,oo)

Range: Any real number of y<=5 or [-oo,5]

graph{-3(x-10)^2+5 [-20, 20, -10, 10]} [Ans]