What is the domain and range of $y=-3/(4x+4)$ ?

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Answer 1 · 2017-03-28T05:43:29

The domain of $y$ is $D_y=RR-{-1}$
The range of $y$ , that is, $R_y=RR-{0}$

As you cannot divide by $0$ ,

$4x+4!=0$

$x!=-1$

The domain of $y$ is $D_y=RR-{-1}$

To find the range, we calculate $y^-1$

$y=-3/(4x+4)$

$(4x+4)y=-3$

$4x+4=-3/y$

$4x=-3/y-4=-(3+4y)/(4y)$

$x=-(3+4y)/(16y)$

Therefore,

$y^-1=-(3+4x)/(16x)$

The domain of $y^-1$ is $=RR-{0}$

This is the range of $y$ , that is, $R_y=RR-{0}$

What is the domain and range of y=-3/(4x+4)y=-3/(4x+4)?