What is the domain and range of y=2^(x-1)+1?

1 Answer
Jul 27, 2017

Domain: (-oo, +oo)
Range: (1, +oo)

Explanation:

y = 2^(x-1)+1 = 2^x/2 +1

y is defined forall x in RR -> the domain of y = (-oo, +oo)

lim_(x->-oo) y = 1

lim_(x->+oo) y = oo

Hence the range of y = (1, +oo)

This can be seen by the graph of y below.

graph{2^(x-1)+1 [-7.78, 6.27, -0.74, 6.285]}