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What is the domain and range of #y=1/(x-1)^2#?

1 Answer

Jan 15, 2018

Domain: #x in RR#, #x ne 1#.
Range: #y>0#

Explanation:

The graph of #y=1/x^2# has domain #x in RR#, #x ne 0# and #y>0#.

#y=1/(x-1)^2# is a horizontal shift of 1 unit to the right, so the new domain is #x in RR#, #x ne 1#. The range does not change, so it's still #y>0#.

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