What is the domain and range of x =(y+2)^2?

1 Answer
Feb 15, 2017

Domain: [0, oo), Range: [-2, oo)

Explanation:

To graph, you need to solve for y:

Square root both sides: sqrt(x) = y+2
Isolate the variable y: y =sqrt(x) -2

Analytically finding the domain:
sqrt(x) >=0 which means x>=0

If x>=0 then y >= -2

From the graph: graph{sqrt(x) - 2 [-10, 10, -5, 5]}