What is the domain and range of $h(x)=(x-1)/(x^3-9x)$ ?

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Answer 1 · 2018-07-12T11:35:51

Domain: $x in (-oo,-3)uu(-3,0)uu(0,3)uu(3,oo)$
Range : $h(x) in RR or (-oo,oo)$

$h(x)=(x-1)/(x^3-9 x) or h(x)=(x-1)/(x(x^2-9)$ or

$h (x)=(x-1)/(x(x+3)(x-3)$

Domain: Possible input value of $x$ , if denominator is

zero , the function is undefined .

Domain: $x$ is any real value except $x=0 , x =-3 and x=3$ .

In interval notation:

$x in (-oo,-3)uu(-3,0)uu(0,3)uu(3,oo)$

Range: Possible output of $h(x)$ .When $x=1 ; h(x)=0$

Range : Any real value of $h(x) :. h(x) in RR or (-oo,oo)$

graph{(x-1)/(x^3-9x) [-10, 10, -5, 5]}[Ans]

What is the domain and range of h(x)=(x-1)/(x^3-9x) h(x)=(x-1)/(x^3-9x) ?