What is the domain and range of h(x)= 1 /x^2?

1 Answer
Ratnaker Mehta
Jul 22, 2016

Domain of h, D_h, is RR-{0}.

Range of h, R_h=(0,oo).

Explanation:

We know that Division by 0 is not permissible , so, we can not take x=0. Except this, x can take any value from RR, which means that the Domain of h, D_h, is RR-{0}.

Next, AA x in D_h, x^2>0, and so is, 1/x^2.

Also let us note that, for each x in D_h, h(x)!=0, because, if for some x in D_h, h(x)=1/x^2=0 rarr 1=0, an impossible result.

Thus, Range of h, R_h=(0,oo).

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