What is the domain and range of $g(x)=(1-x^2)$ ?

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What is the domain and range of $g(x)=(1-x^2)$ ?

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Answer 1 · 2016-03-01T13:02:10

domain would be (-infinity to infinity)

Answer 2 · 2016-03-01T13:10:22

The domain would be unlimited, as there are no 'forbidden' values for $x$ (no fractions, no roots).
Domain $=(-oo,+oo)$

Explanation:

For the range we observe that the maximum value of $g(x)$ happens when $x=0$ (which means the least to subtract from 1).
Any other value of $x$ would make $x^2>0->g(x)<1$
Range $=(-oo,1]$

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What is the domain and range of $g(x)=(1-x^2)$ ?

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