What is the domain and range of g(x) = 1/(7-x)^2g(x)=1(7x)2?

1 Answer
Aug 13, 2015

Domain: (-oo, 7) uu (7, + oo)(,7)(7,+).
Range: (0, +oo)(0,+)

Explanation:

The domain of the function will have to take into account the fact that the denominator cannot be equal to zero.

This means that any value of xx that will make the denominator equal to zero will be excluded from the domain.

In your case, you have

(7-x)^2 = 0 implies x = 7(7x)2=0x=7

This means that the domain of the function will be RR - {7}, or (-oo, 7) uu (7, + oo).

To find the range of the function, first note that a fractional expression can only be equal to zero if the numerator is equal to zero.

In your case, the numberator is constant and equal to 1, which means that you cannot find an x for which g(x) = 0.

Moreover, the denominator will always be positive, since you're dealing with a square. This means that the range of the function will be (0, +oo).

graph{1/(7-x)^2 [-20.28, 20.27, -10.14, 10.12]}