What is the domain and range of #f(x) = sqrt(x - 8)#?

1 Answer
Gió
Mar 26, 2015

The domain is given setting the argument bigger or equal to zero to avoid a negative square root:
#x-8>=0#
So the domain is all the real #x# bigger or equal to #8#.
The range must be all the #y# bigger or equal to #0# because your square root cannot devolve a negative value.

Graphically:
graph{sqrt(x-8) [-0.45, 50.86, -4.48, 21.2]}

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