What is the domain and range of f(x) = sqrt(x - 8)?

1 Answer
Gió
Mar 26, 2015

The domain is given setting the argument bigger or equal to zero to avoid a negative square root:
x-8>=0
So the domain is all the real x bigger or equal to 8.
The range must be all the y bigger or equal to 0 because your square root cannot devolve a negative value.

Graphically:
graph{sqrt(x-8) [-0.45, 50.86, -4.48, 21.2]}

Related questions
See all questions in Domain and Range of a Function
Impact of this question
10166 views around the world
You can reuse this answer
Creative Commons License