What is the domain and range of f(x) = 1/(2x+4)?

1 Answer
Jan 28, 2017

The domain is x in RR- {-2}
The range is f(x) in RR-{0}

Explanation:

As we cannot divide by 0, x!=-2

The domain of f(x) is D_f(x)=RR-{-2}

lim_(x->-oo)f(x)=lim_(x->-oo)1/(2x)=0^-

lim_(x->+oo)f(x)=lim_(x->+oo)1/(2x)=0^+

Therefore,

f(x)!=0

The range of f(x) is R_f(x)=RR-{0}