What is the domain and range of $f (t) = \sqrt{9 - t^{2}}$ $f(t) = sqrt(9-t^2)$ ?

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Answer 1 · 2015-09-27T08:52:02

Domain ${t:RR, -3<=t<=3}$

Range ${f(t):RR, 0<=f(t)<=3}$

For real f(t), $9>=t^2$ or $3>= +-t$ . That is $-3<=t<=3$ would be the domain of f(t).

For range, f(t) would be 0 for t =3 or -3, it would be maximum at t=0

hence range would be ${f(t) : RR, 0<=f(t)<=3}$

What is the domain and range of f(t) = sqrt(9-t^2)f(t)=√9−t2f(t) = sqrt(9-t^2)?