What is the domain and range of $d(s)= 0.009s^2$ ?

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Answer 1 · 2015-08-24T12:40:29

There is no restriction on the domain (no radicals or fractions)

So domain $=(-oo,+oo)$

Since $d(s)$ is a square and therefore never negative, the range is restricted to non-negative numbers, the smallest being $d(0)=0$

So range $=(0,+oo)$

What is the domain and range of d(s)= 0.009s^2d(s)= 0.009s^2?