What is the domain and range for $y = sqrt(x-3)$ ?

Question

6266 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-05-18T21:11:16

You know $sqrt(a)$ is well defined iff $a>=0$ (otherwise its image is not in $RR$ ), so $y$ is well defined iff

$x-3>=0 => x>=3$

Its range is the range of the square root, so $y>=0$

What is the domain and range for y = sqrt(x-3)y = sqrt(x-3)?