What is the derivative of $y = arcsin (3 x + 5)$ $y=arcsin(3x+5)$ ?

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Answer 1 · 2015-09-13T11:46:37

It is $\frac{d y}{d x} = ⎛ ⎜ ⎜ ⎝ \frac{3}{\sqrt{1 - (3 x + 5^{2})}} ⎞ ⎟ ⎟ ⎠$ $dy/dx=(3/sqrt(1-(3x+5^2)))$

The derivative of $y = arcsin g (x)$ $y=arcsing(x)$ is

$dy/dx=(g'(x))/sqrt(1-g^2(x))$ where g(x)=3x+5

hence we have that

$dy/dx=(3/sqrt(1-(3x+5^2)))$

What is the derivative of y=arcsin(3x+5)y=arcsin(3x+5)y=arcsin(3x+5)?