What is the derivative of this function $y=tan^-1(x^3)-x$ ?

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Answer 1 · 2016-09-15T03:32:38

$dy/dx = (3x^2)/(x^6+1)-1$

$y = arctan(x^3)-x$

$dy/dx= 1/((x^3)^2+1) * d/dx(x^3) -d/dx x$ (Standard differential and chain rule)

$= 1/(x^6+1) * 3x^2 -1$ (Power rule)

$= (3x^2)/(x^6+1)-1$

What is the derivative of this function y=tan^-1(x^3)-xy=tan^-1(x^3)-x?