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What is the derivative of this function #y=tan^-1(x^3)-x#?

1 Answer

Sep 15, 2016

#dy/dx = (3x^2)/(x^6+1)-1#

Explanation:

#y = arctan(x^3)-x#

#dy/dx= 1/((x^3)^2+1) * d/dx(x^3) -d/dx x# (Standard differential and chain rule)

#= 1/(x^6+1) * 3x^2 -1# (Power rule)

#= (3x^2)/(x^6+1)-1#

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