What is the derivative of this function $y=sin^-1sqrtx$ ?

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Answer 1 · 2017-03-23T05:48:49

$dy/dx= 1/(2sqrt(1-x)sqrt(x)$

$y =sin^-1 sqrtx$

Applying the standard differential and the chain rule

$dy/dx= 1/sqrt(1-(sqrtx)^2) * 1/2x^(-1/2)$

$= 1/(sqrt(1-x)* 2sqrt(x)$

$= 1/(2sqrt(1-x)sqrt(x)$

What is the derivative of this function y=sin^-1sqrtxy=sin^-1sqrtx?