What is the derivative of this function y=sin^-1(e^x)? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Eddie Aug 12, 2016 \ y' =(e^x)/sqrt(1 - e^(2x)) Explanation: y=sin^-1(e^x) sin y= e^x cos y \ y' = e^x \ y' =(e^x)/cos y \ y' =(e^x)/sqrt(1 - sin^2 x) \ y' =(e^x)/sqrt(1 - (e^x)^2) \ y' =(e^x)/sqrt(1 - e^(2x)) Answer link Related questions What is the derivative of f(x)=sin^-1(x) ? What is the derivative of f(x)=cos^-1(x) ? What is the derivative of f(x)=tan^-1(x) ? What is the derivative of f(x)=sec^-1(x) ? What is the derivative of f(x)=csc^-1(x) ? What is the derivative of f(x)=cot^-1(x) ? What is the derivative of f(x)=(cos^-1(x))/x ? What is the derivative of f(x)=tan^-1(e^x) ? What is the derivative of f(x)=cos^-1(x^3) ? What is the derivative of f(x)=ln(sin^-1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 21027 views around the world You can reuse this answer Creative Commons License