What is the derivative of this function $y=sin^-1(2x)$ ?

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Answer 1 · 2016-08-03T09:07:46

$(dy)/(dx)=2/sqrt(1-4x^2)$

We can use here the formula for derivative of $sin^(-1)x$ , which is $d/(dx)sin^(-1)x=1/sqrt(1-x^2)$

As such to find derivative $(dy)/(dx)$ for $y=sin^(-1)2x$ using chain rule is given by

$(dy)/(dx)=1/sqrt(1-(2x)^2)xxd/(dx)(2x)$

= $2/sqrt(1-4x^2)$

What is the derivative of this function y=sin^-1(2x)y=sin^-1(2x)?