What is the derivative of this function #y = sin^-1(x^2)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Noah G · mason m Sep 5, 2016 #dy/dx = (2x)/sqrt(1 - x^4)# Explanation: #siny = x^2# #cosy(dy/dx) = 2x# #dy/dx = (2x)/cosy# #dy/dx = (2x)/sqrt(1 - sin^2y)# #dy/dx=(2x)/sqrt(1-(x^2)^2)# #dy/dx = (2x)/sqrt(1 - x^4)# Hopefully this helps! Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 42399 views around the world You can reuse this answer Creative Commons License