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What is the derivative of #tan^ -1(3x^2)#?

1 Answer

Leland Adriano Alejandro

Jan 10, 2016

first derivative of #tan^-1 (3x^2)# is

#(6x)/(1+9x^4)#

Explanation:

the formula #d/dx(tan^-1 u)=((du)/dx)/(1+u^2)#

#d/dx(tan^-1(3x^2))=(d/dx(3x^2))/(1+(3x^2)^2#

#d/dx(tan^-1(3x^2))=(6x)/(1+9x^4)#

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