What is the derivative of $tan^ -1(3x^2)$ ?

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Answer 1 · 2016-01-10T11:39:58

first derivative of $tan^-1 (3x^2)$ is

$(6x)/(1+9x^4)$

the formula $d/dx(tan^-1 u)=((du)/dx)/(1+u^2)$

$d/dx(tan^-1(3x^2))=(d/dx(3x^2))/(1+(3x^2)^2$

$d/dx(tan^-1(3x^2))=(6x)/(1+9x^4)$

What is the derivative of tan^ -1(3x^2)tan^ -1(3x^2)?