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What is the derivative of #f(x) = e^x/lnx#?

1 Answer

Mar 12, 2018

#d/dx (e^x/lnx) = (e^x(xlnx-1))/(xln^2x)#

Explanation:

Using the quotient rule:

#d/dx (f/g) = (g * (df)/dx -f *(dg)/dx)/g^2#

we have:

#d/dx (e^x/lnx) = (e^xlnx - e^x/x)/(ln^2x)#

#d/dx (e^x/lnx) = (e^x(xlnx-1))/(xln^2x)#

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