What is the derivative of #f(t) = ((lnt)^2-t, tcsct ) #?
1 Answer
Mar 25, 2016
f'(t) =
Explanation:
f(t) = ( x(t), y(t0).
f'(t) = ( x'(t), y'(t)).
x(t) =
Applying function of function rule, f'(t)=2uu'(t)-1=
y(t) = t csc t.
Applying product rule,
y'(t) =