What is the derivative of #cot^-1(x)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Sonnhard Jun 9, 2018 #dy/dx=-1/(x^2+1)# Explanation: Let #y=arccot(x)# then #cot(y)=x# so #-csc^2(y)dy/dx=1# #dy/dx=-1/csc^2(x)# #dy/dx=-1/(1+cot^2(y))# #dy/dx=-1/(1+x^2)# since #cot(y)=x# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 32709 views around the world You can reuse this answer Creative Commons License