What is the derivative of $arctan (x/2)$ ?

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Answer 1 · 2016-06-26T07:29:17

$(dy)/(dx)=1/2cos^2(arctan(x/2))$

As $y=arctan(x/2)$

$tany=x/2$

Hence, $sec^2yxx(dy)/(dx)=1/2$ or

$(dy)/(dx)=1/2cos^2y=1/2cos^2(arctan(x/2))$

What is the derivative of arctan (x/2)arctan (x/2)?