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What is the derivative of #arctan(x^2+1)#?

1 Answer

Feb 27, 2016

#(2x)/(1+(x^2+1)^2)#

Explanation:

From the rules, #d/dxtan^(-1)[u(x)]=1/(1+u^2)*(du)/dx#

we get

#d/dxtan^(-1)(x^2+1)=1/(1+(x^2+1)^2)*2x#

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