What is the derivative of #arctan(x-1)#?

1 Answer
mason m
Mar 18, 2016

#d/dx(arctan(x-1))=1/(x^2+2x+2)#

Explanation:

We must first know the derivative of #arctan(x)#, which is:

#d/dxarctan(x)=1/(1+x^2)#

According to the chain rule, we see that

#d/dxarctan(f(x))=1/(1+(f(x))^2)*f'(x)#

So, for #arctan(x-1)#, we see that #f(x)=x-1# and #f'(x)=1#.

#d/dxarctan(x-1)=1/(1+(x-1)^2)*1#

#=1/(1+(x^2-2x+1)#

#=1/(x^2-2x+2)#

Related questions
See all questions in Differentiating Inverse Trigonometric Functions
Impact of this question
1595 views around the world
You can reuse this answer
Creative Commons License