What is the derivative of #arctan(x)^(1/2)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Michael Sep 3, 2015 #f'(x)=(1)/(2sqrt(x)(1+x)# Explanation: #f(x)=arctan(x^(1/2))# Using the chain rule: #f'(x)=(1)/(1+x)xx1/2x^(-1/2)# #f'(x)=(x^(-1/2))/(2(1+x))# #f'(x)=(1)/(2sqrt(x)(1+x)# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1140 views around the world You can reuse this answer Creative Commons License