What is the derivative of Arctan(sqrt(5x))? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer James May 7, 2018 the answer d/dx[Arctan(sqrt(5x))]=[5/(2sqrt5x)]/[1+5x]=sqrt(5)/(2sqrt(x)*(5x+1)) Explanation: note that d/dx[arctan(u)]=((du)/dx)/[1+u^2] now let's derive Arctan(sqrt(5x)) d/dx[Arctan(sqrt(5x))]=[5/(2sqrt5x)]/[1+5x]=sqrt(5)/(2*sqrt(x)*(5*x+1)) Answer link Related questions What is the derivative of f(x)=sin^-1(x) ? What is the derivative of f(x)=cos^-1(x) ? What is the derivative of f(x)=tan^-1(x) ? What is the derivative of f(x)=sec^-1(x) ? What is the derivative of f(x)=csc^-1(x) ? What is the derivative of f(x)=cot^-1(x) ? What is the derivative of f(x)=(cos^-1(x))/x ? What is the derivative of f(x)=tan^-1(e^x) ? What is the derivative of f(x)=cos^-1(x^3) ? What is the derivative of f(x)=ln(sin^-1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 4027 views around the world You can reuse this answer Creative Commons License