What is the derivative of arctan(cosθ)?
1 Answer
Feb 14, 2016
-sintheta/(1 +cos^2theta)
Explanation:
using the following facts :
d/dx(tan^-1x) = 1/(1 + x^2) differentiating using the
color(blue)(" chain rule ")
d/dx[f(g(x))] = f'g(x).g'(x)
d/dx[tan^-1(costheta)] = 1/(1 + cos^2theta) d/dx(costheta)
= -sintheta/(1+ cos^2theta)
