What is the derivative of $arctan(2x)$ ?

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Answer 1 · 2015-06-06T16:51:17

The general rule for derivating this type of function is

$y=arctan(u)$

$y'=(u')/(1+u^2)$

Thus, considering that here $u=2x$

$y'=2/(1+(2x)^2)=2/(1+4x^2)$

Done! :)

What is the derivative of arctan(2x)arctan(2x)?