What is the derivative of arcsin(x^2/4)? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Matt B. Nov 22, 2016 d/dx(arcsin(x^2/4)) = x/(2sqrt(1-x^4/16)) Explanation: Let u=x^2/4 d/dx(arcsinu) = 1/sqrt(1-u^2) * d/dx(u) d/dx(u) = x/2 The rest is just plugging in and multiplying u. Answer link Related questions What is the derivative of f(x)=sin^-1(x) ? What is the derivative of f(x)=cos^-1(x) ? What is the derivative of f(x)=tan^-1(x) ? What is the derivative of f(x)=sec^-1(x) ? What is the derivative of f(x)=csc^-1(x) ? What is the derivative of f(x)=cot^-1(x) ? What is the derivative of f(x)=(cos^-1(x))/x ? What is the derivative of f(x)=tan^-1(e^x) ? What is the derivative of f(x)=cos^-1(x^3) ? What is the derivative of f(x)=ln(sin^-1(x)) ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1708 views around the world You can reuse this answer Creative Commons License