What is the derivative of $arcsin(3-x^2)$ ?

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Answer 1 · 2015-06-07T23:34:14

The derivative for $arcsinu$ is:

$d/(dx)[arcsinu(x)] = 1/(sqrt(1-u^2))*(du(x))/(dx)$

$d/(dx)[arcsin(3-x^2)] = 1/(sqrt(1-(3-x^2)^2))*(-2x)$

$= -(2x)/(sqrt(1-(3-x^2)^2))$

What is the derivative of arcsin(3-x^2)arcsin(3-x^2)?