What is the derivative of #arcsin(3-x^2)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Truong-Son N. Jun 7, 2015 The derivative for #arcsinu# is: #d/(dx)[arcsinu(x)] = 1/(sqrt(1-u^2))*(du(x))/(dx)# #d/(dx)[arcsin(3-x^2)] = 1/(sqrt(1-(3-x^2)^2))*(-2x)# #= -(2x)/(sqrt(1-(3-x^2)^2))# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1236 views around the world You can reuse this answer Creative Commons License